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From Loren Siebert <>
Subject Re: Regex and serde with hive
Date Fri, 23 Dec 2011 07:27:15 GMT
The input regexp does not look right to me. You are expecting a space between groups, but your
example contains no spaces. And where do you handle the first/last quotes? Wouldn’t it look
more like this:
"input.regex" = “\"([^\"~]*)[\"~]*([^\"~]*)[\"~]*([^\"~]*)\""

Rather than trying to tackle it all at once, I find it easier to start with a table of one
column and then build up from there until I have all my columns.

On Dec 22, 2011, at 8:49 PM, Raghunath, Ranjith wrote:

> I have been struggling with this for a while so I would appreciate any advice that you
any of you may have.
> I have a file of the format
> “Xyz”~”qsd”~”1234”
> I created the following table definition to get the data loaded
> (f1   string,
>   f2    string,
>   f3     string)
> ROW FORMAT SERDE 'org.apache.hadoop.hive.contrib.serde2.RegexSerDe'
> "input.regex" = "([^\"~]*) ([^\"~]*) ([^\"~]*)?",
> "output.format.string" = "%1$s %2$s %3$s");
> When I load the data in and try to perform a select get NULL values. Thanks again.
> Thank you,
> Ranjith

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