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From Roland Weber <ROLWE...@de.ibm.com>
Subject Re: how do u simulate sending a blank file field with httpclient?
Date Mon, 07 Mar 2005 08:12:53 GMT
Hello Steve,

you can implement a PartSource that returns 0 as the
content length, an empty string as the file name, and
ByteArrayInputStream(new byte[0]) as the InputStream.

And yes, it does make sense.

hope that helps,

06.03.2005 22:09
Please respond to
"HttpClient User Discussion"


how do u simulate sending a blank file field with httpclient?

Ive been trying to figure out how to send a blank file field with 

Ive managed to work out how to use the multipartform encoded http post and 
can send a file ok, but what i would like to do is to be able to post a 
filepart but not actually send a file, which would simulate a person 
submitting a form that includes a file field, but they havent actually 
chosen a file to submit. 

i hope that makes sense?

the actual http headers that are submitted when no file is selected and 
the form is submitted looks something like this:

Content-Disposition: form-data; name="SomeFile"; filename=""
Content-Type: application/octet-stream

i have tried things like creating a null file for the filepart or making 
the filename "", but both these methods caused an exception to be thrown.

does anyone know the correct way of doing this? 



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