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From Stack <st...@duboce.net>
Subject Re: Query a version of a column efficiently
Date Thu, 26 Jul 2012 22:30:57 GMT
On Thu, Jul 26, 2012 at 11:40 PM, Jerry Lam <chilinglam@gmail.com> wrote:
> Hi St.Ack:
>
> Let say there are 5 versions for a column A with timestamp = [0, 1, 3, 6,
> 10].
> I want to execute an efficient query that returns one version of the column
> that has a timestamp that is equal to 5 or less. So in this case, it should
> return the value of the column A with timestamp = 3.
>
> Using the setTimeRange(5,  Long.MAX_VALUE) with setMaxVersion = 1, my guess
> is that it will return the version 6 not version 3. Correct me if I'm
> wrong.
>

What Tom says, try it.  IIUC, it'll give you your 3.  It won't give
you 6 since that is outside of the timerange (try 0 instead of
MAX_VALUE; I may have misled w/ MAX_VALUE... it might work but would
have to check code).

St.Ack

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