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From "Arun C Murthy (JIRA)" <j...@apache.org>
Subject [jira] Commented: (HADOOP-4981) Prior code fix in Capacity Scheduler prevents speculative execution in jobs
Date Mon, 12 Jan 2009 22:00:00 GMT

    [ https://issues.apache.org/jira/browse/HADOOP-4981?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=12663113#action_12663113
] 

Arun C Murthy commented on HADOOP-4981:
---------------------------------------

bq. Check if the TT has enough mem for the job. If yes, obtain a task from the job, as before.
If not, determine whether the job has a task to run.

If the TT doesn't have enough memory for the job's tasks, what is the point trying to check
if the job has a task to run?

I think the capacity scheduler should just ask for a task iff the TT has enough memory and
the let the JobInProgress hand out normal, failed or speculative tasks as is done in the default
scheduler.

> Prior code fix in Capacity Scheduler prevents speculative execution in jobs
> ---------------------------------------------------------------------------
>
>                 Key: HADOOP-4981
>                 URL: https://issues.apache.org/jira/browse/HADOOP-4981
>             Project: Hadoop Core
>          Issue Type: Bug
>          Components: contrib/capacity-sched
>            Reporter: Vivek Ratan
>            Priority: Blocker
>         Attachments: 4981.1.patch
>
>
> As part of the code fix for HADOOP-4035, the Capacity Scheduler obtains a task from JobInProgress
(calling obtainNewMapTask() or obtainNewReduceTask()) only if the number of pending tasks
for a job is greater than zero (see the if-block in TaskSchedulingMgr.getTaskFromJob()). So,
if a job has no pending tasks and only has running tasks, it will never be given a slot, and
will never have a chance to run a speculative task. 

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