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From: "Nelson, Erick" <Erick.Nelson@hdsupply.com>
To: "users@groovy.apache.org" <users@groovy.apache.org>
Subject: Re: Looping through a hashmap & removing elements
Thread-Topic: Looping through a hashmap & removing elements
Thread-Index: AQHRvPsu50+A9IXv00asjXWbomkJ3Z/WS+gA
Date: Thu, 2 Jun 2016 18:25:04 +0000
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archived-at: Thu, 02 Jun 2016 18:25:18 -0000


Does something like this work?

uidMap.keySet().removeAll(uidMap.findAll{it.key =3D=3D '?'}.keySet())


From: Guy Matz <guymatz@gmail.com<mailto:guymatz@gmail.com>>
Reply-To: "users@groovy.apache.org<mailto:users@groovy.apache.org>" <users@=
groovy.apache.org<mailto:users@groovy.apache.org>>
Date: Thursday, June 2, 2016 at 11:18 AM
To: "users@groovy.apache.org<mailto:users@groovy.apache.org>" <users@groovy=
.apache.org<mailto:users@groovy.apache.org>>
Subject: Looping through a hashmap & removing elements

Hi!  I want to loop through a hashmap and delete some elements based on som=
e criteria . . .  I thought there would be some slick groovy method - in th=
e spirit of findAll, etc. - to do this, but couldn't find it . . .  my java=
 developer workmate suggested:


iter =3D uidMap.entrySet().iterator()
while (iter.hasNext()) {
    entry =3D iter.next()
    key =3D entry.key
    value =3D entry.value

    if (bla, blah, blah) {

        iter.remove()

    }


Is there a groovier way?


Thanks!

Guy