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From Thorsten Scherler <thors...@apache.org>
Subject Re: coding dynamicall in xdocs/ and to delimit output in meta-data?
Date Mon, 05 Sep 2005 17:45:28 GMT
On Mon, 2005-09-05 at 15:59 +0100, Ross Gardler wrote:
> Helena Edelson wrote:
> > <xsl:for-each select="(articles/article[@type='foo'][position() &lt; 5 ]">
> >   
> > I think the directive I am not understanding is what
> > position() &lt; 5 
> > is doing. Is it checking an array or vector of types and saying if not null
> > return 0-4?
> 
> The last part simply says if the position of a node within the list of 
> nodes returned by the previous statements is leff than 5 then include it 
> in the result set. Anything in a square bracket is a test.
> 
> > And I then have those ready for my out.print?
> 
> Not sure what you mean by out.print, there is no such concept in XSLT. 
> However, yes, the nodes that pass the tests in the XPath statement are 
> available to whatever you have inside the for-each loop.
> 
> Like I said earlier this list is not a good place to be looking for 
> general XSLT help. You would be far better going through the tutorials 
> on http://www.zvon.org, of course, if you have an XSLT problem specific 
> to Forrest, we will be glad to help.
> 

In addition, one of the best (if not *the* best) xsl mailing list on the
planet:
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salu2
-- 
thorsten

"Together we stand, divided we fall!" 
Hey you (Pink Floyd)


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