Le 6/22/12 9:09 PM, Carlo.Accorsi@ibs-ag.com a écrit :
> OK, Thank you very much for the clarification. I really thought I had it right.
> Last question on this. In the case where the length after the 0x80 is> 1. As below, where the length is 2.
>
> 30, 9, a0, 4, 80, 2, 0, d0, 81, 1, 2,
> Do you know how to decode the int value?
Just for the record, an integer above 0x7F and below7FFF will be encoded
on 2 bytes. If the higher bit is 0, then the value is positive.
> I'm looking for 208, which is 0xd0 but not sure what to do with the other 0x00 byte?
It's just there because you want a positive integer above 0x7F. Would
you have 0x01 0xD0, it would be a negative value (-47).
--
Regards,
Cordialement,
Emmanuel Lécharny
www.iktek.com