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From "Dag H. Wanvik (JIRA)" <j...@apache.org>
Subject [jira] Commented: (DERBY-4471) Left outer join reassociation rewrite gives wrong result
Date Tue, 17 Aug 2010 20:23:16 GMT

    [ https://issues.apache.org/jira/browse/DERBY-4471?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=12899561#action_12899561
] 

Dag H. Wanvik commented on DERBY-4471:
--------------------------------------

Thanks for looking at this, Rick. 

The thrust of this patch is not transformation of outer join to *inner* join, but rather reassociating
one form of left outer join (right deep) to another form of left outer join (left deep). The
new Javadoc for HalfOuterJoinNode#LOJ_reorderable and HalfOuterJoinNode#isNullRejecting
is intended to explain how this now works. If you find this confusing, let me know and I'll
try to improve it.

As for the transformation of outer join to inner join (HalfOuterJoinNode#transformOuterJoins),
this patch doesn't touch that, but the condition is related: The must exist a null intolerant
predicate on the inner table.

> Left outer join reassociation rewrite gives wrong result
> --------------------------------------------------------
>
>                 Key: DERBY-4471
>                 URL: https://issues.apache.org/jira/browse/DERBY-4471
>             Project: Derby
>          Issue Type: Bug
>          Components: SQL
>    Affects Versions: 10.0.2.0, 10.0.2.1, 10.1.1.0, 10.1.2.1, 10.1.3.1, 10.2.1.6, 10.2.2.0,
10.3.1.4, 10.3.2.1, 10.3.3.0, 10.4.1.3, 10.4.2.0, 10.5.1.1, 10.5.2.0, 10.5.3.0
>            Reporter: Dag H. Wanvik
>            Assignee: Dag H. Wanvik
>         Attachments: derby-4471-1a.diff, derby-4471-1a.stat, derby-4471-1b.diff, derby-4471-1b.stat,
derby-4471-1c.diff, derby-4471-1c.stat, derby-4471-junit-repro.diff, query_plan_derby_4471.pdf
>
>
> The following script and output shows the problem:
> > create table r(c1 char(1));
> > create table s(c1 char(1), c2 char(1));
> > create table t(c1 char(1));
> > insert into r values 'a';
> > insert into s values ('b', default);
> > insert into t values ('c');
> > select * from s left outer join t on s.c2=t.c1 or s.c2 is null;
> C1  |C2  |C1  
> --------------
> b   |NULL|c   
> > select * from r left outer join s on r.c1=s.c1;
> C1  |C1  |C2  
> --------------
> a   |NULL|NULL
> > select * from (r left outer join s on r.c1=s.c1) left outer join t on s.c2=t.c1
or s.c2 is null;
> C1  |C1  |C2  |C1  
> -------------------
> a   |NULL|NULL|c   
> > select * from r left outer join (s left outer join t on s.c2=t.c1 or s.c2 is null)
on r.c1=s.c1;
> C1  |C1  |C2  |C1  
> -------------------
> a   |NULL|NULL|c   
> The last result is wrong. The correct answer should be:
> C1  |C1  |C2  |C1  
> -------------------
> a   |NULL|NULL|NULL   
> since in the last form, the left table r has the value 'a', which does
> not match any row in result of the compound inner given the join
> predicate ("r.c1=s.c1"), so all nulls should be appended to the 'a'
> from the outer table r.
> This happens because internally the last form is rewritten to the
> second but the last form (left-deep), but this rewrite is not
> justified here unless the join predicate on s rejects null, which the
> present one explicitly does not ("or s.c2 is null"). Cf. for example
> [1], page 52, which describes this transform and its prerequisite
> condition as indentity #7.
> [1] Galindo-Legaria, C. & Rosenthal, A.: "Outerjoin simplification and
> reordering for query optimization", ACM Transactions on Database
> Systems, Vol 22, No 1, March 1997.

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