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From: "Ganesan, Chandru" <chandru.ganesan@hp.com>
To: "users@cxf.apache.org" <users@cxf.apache.org>
Subject: WebClient request to HTTPS URL 
Thread-Topic: WebClient request to HTTPS URL 
Thread-Index: Ac1UjUX/5xCSsoGOTieKMj38j4DiyQ==
Date: Wed, 27 Jun 2012 17:50:04 +0000
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Hi

I could successfully use WebClient to make plain HTTP requests to the serve=
r. Now I'd like to change the request URL to HTTPS. Is there any special ha=
ndling needed for this in the client code.

I'm getting following error when accessing an HTTPS URL:

[No Trust Decider for Conduit '{https://<suppressing the url in email>:443}=
 WebClient.http-conduit'. An afirmative Trust Decision is assumed.]
[Interceptor for {https:// ://<suppressing the url in email>:443}WebClient =
has thrown exception, unwinding now]
org.apache.cxf.interceptor.Fault: Could not send Message.
                at org.apache.cxf.interceptor.MessageSenderInterceptor$Mess=
ageSenderEndingInterceptor.handleMessage(MessageSenderInterceptor.java:64)
                at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(P=
haseInterceptorChain.java:243)
                at org.apache.cxf.jaxrs.client.WebClient.doChainedInvocatio=
n(WebClient.java:595)
                at org.apache.cxf.jaxrs.client.WebClient.doInvoke(WebClient=
.java:576)
                at org.apache.cxf.jaxrs.client.WebClient.invoke(WebClient.j=
ava:323)
                at org.apache.cxf.jaxrs.client.WebClient.get(WebClient.java=
:390)

Appreciate the help

Thanks
Chandru

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