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From "Bruno P. Kinoshita" <brunodepau...@yahoo.com.br.INVALID>
Subject Re: [CSV] Record Separator query
Date Sat, 26 Aug 2017 12:34:50 GMT
Ok, so uploaded my keys, followed the steps at https://commons.apache.org/releases/prepare.html, used
the commit logs in other commons repositories to see what was done for a new release.

I stopped just before the step to Tag the Release Candidate.

Should I proceed and give it a try at my first attempt at releasing a commons component and
prepare the vote for CSV 1.5 RC1?

Or should we wait for the mutable record ongoing discussion in the mailing list?

If anyone would like to take a peek and check if I missed anything before I call the vote,
any feedback would be welcome :) https://github.com/apache/commons-csv/compare/release...kinow:release?expand=1

Cheers
Bruno


________________________________
From: Gary Gregory <garydgregory@gmail.com>
To: Commons Users List <user@commons.apache.org>; Bruno P. Kinoshita <brunodepaulak@yahoo.com.br>
Sent: Sunday, 13 August 2017, 4:24:34 PM NZST
Subject: Re: [CSV] Record Separator query

On Sat, Aug 12, 2017 at 8:48 PM, Bruno P. Kinoshita <brunodepaulak@yahoo.com.br.invalid>
wrote:
> Hmmm, for a while I have been considering learning how to release Commons components.
Maybe I could start with Commons CSV, though I could do with some help :) I will start reading
the docs at https://commons.apache.org/ releases/index.html. Is there anything else I need
to know to act as RM?

Patience :-) there are lots of details.

Gary
 
>  CheersBruno
> 
> 
> On Sunday, 13 August 2017, 4:08:36 AM NZST, Gary Gregory <garydgregory@gmail.com>
wrote:
> 
> There is no one currently slated to volunteer to RM the release. Good time
> to ask though!
> 
> Do have a committer here willing to volunteer to release Commons CSV 1.5?
> 
> Thank you,
> Gary
> 
> On Fri, Aug 11, 2017 at 3:27 PM, nitin mahendru <nitin.mahendru88@gmail.com>
> wrote:
> 
>> Thanks for accepting the pull request.
>> Any pointers on when the version 1.5 will be released ?
>>
>>
>>
>>
>> On Thu, Aug 10, 2017 at 2:19 PM nitin mahendru <nitin.mahendru88@gmail.com
>> >
>> wrote:
>>
>> > Thanks Greg.
>> > Well the problem actually was that I am behind a proxy.  So my mistake.
>> > Sorry for that.
>> >
>> > I have raised a pull request and a JIRA item CSV-214. Looking forward to
>> > your feedback.
>> >
>> > Thanks
>> >
>> > Nitin
>> >
>> >
>> >
>> >
>> > On Thu, Aug 10, 2017 at 1:08 PM Gary Gregory <garydgregory@gmail.com>
>> > wrote:
>> >
>> >> Use the button provided by GitHub to copy the repo URL to the clipboard,
>> >> then you can just use "git clone <PASTE>"
>> >>
>> >> On Thu, Aug 10, 2017 at 1:05 PM, nitin mahendru <
>> >> nitin.mahendru88@gmail.com>
>> >> wrote:
>> >>
>> >> > Hello All,
>> >> >
>> >> > I raised a JIRA ticket(CSV-214) to make some changes to the code for
>> >> what I
>> >> > a trying to do. The description on the ticket might help explain
>> things
>> >> > better. Now I am trying to clone the repo to make a pull request but
I
>> >> am
>> >> > just stuck at this:
>> >> >
>> >> > git -c http.sslVerify=false clone https://github.com/apache/
>> >> > commons-csv.git
>> >> > Cloning into 'commons-csv'...
>> >> > fatal: https://github.com/apache/ commons-csv.git/info/refs not valid:
>> >> is
>> >> > this a git repository?
>> >> >
>> >> >
>> >> > Any Idea about this ?
>> >> >
>> >> > Thanks
>> >> >
>> >> > Nitin
>> >> >
>> >> >
>> >> >
>> >> >
>> >> >
>> >> > On Wed, Aug 9, 2017 at 5:17 PM Gary Gregory <garydgregory@gmail.com>
>> >> > wrote:
>> >> >
>> >> > > On Wed, Aug 9, 2017 at 5:04 PM, Guang Chao <
>> guang.chao.1974@gmail.com
>> >> >
>> >> > > wrote:
>> >> > >
>> >> > > > On Wed, Aug 9, 2017 at 6:12 AM, nitin mahendru <
>> >> > > nitin.mahendru88@gmail.com
>> >> > > > >
>> >> > > > wrote:
>> >> > > >
>> >> > > > > Hello All,
>> >> > > > >
>> >> > > > > I am trying to read in a csv file which may be 'crlf'
or 'lf'
>> >> > > seperated.
>> >> > > > > Then I want to change a particular column, say encrypt
it and
>> then
>> >> > > write
>> >> > > > > back a new csv with that updated column. I want to use
the same
>> >> > record
>> >> > > > > separator as was in the input file.
>> >> > > > >
>> >> > > > > Is there a way to get the record separator back from
the
>> CSVParser
>> >> > > > object ?
>> >> > > > > I am planning to use the below method to get the writer.
>> >> > > > > CSVFormat.RFC4180. withRecordSeparator(<need to add
record
>> >> > > > > separator).print()
>> >> > > > >
>> >> > > > > For using the above I need to know the record separator
upfront
>> >> > which I
>> >> > > > > have no clue about as the Parser object does not expose
that
>> >> detail.
>> >> > > > >
>> >> > > > > thanks
>> >> > > > >
>> >> > > > > Nitin
>> >> > > > >
>> >> > > >
>> >> > > > I think CSVParser is strict and may not work for both LF
and CRLF.
>> >> > Maybe
>> >> > > > try to scan the file first and see if line ending is lf or
crlf,
>> and
>> >> > then
>> >> > > > use a corresponding CSVParser instance that can handle each
case.
>> >> > > >
>> >> > >
>> >> > > That's not how it works now but feel free to provide a PR on GitHub
>> >> ;-)
>> >> > >
>> >> > > Gary
>> >> > >
>> >> > > >
>> >> > > > --
>> >> > > > Guang <http://javadevnotes.com/java- string-split-newline-examples
>> >
>> >> > > >
>> >> > >
>> >> >
>> >>
>> >
>>
> 

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