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From "Kulpanowski, David" <>
Subject [math] Poisson distribution to show how many ambulances are dispatched per hour
Date Mon, 31 Aug 2015 16:21:23 GMT
I am working on a relatively simple project. I am attempting to generate a Poisson distribution
for the number of ambulances that are dispatched. I have looked at my database and determined
the average number of ambulances dispatched is 9
How do I get a Poisson distribution to be generated using the Commons Math?

The output I am expecting to generate looks like this....

Likelihood of 1 ambulance dispatched is 0.005
Likelihood of 2 ambulances dispatched is 0.015
Likelihood of 3 ambulances dispatched is 0.034
Likelihood of 4 ambulances dispatched is 0.61
Likelihood of 5 ambulances dispatched is 0.091
Likelihood of 6 ambulances dispatched is 0.117

This is probably a very simple programming question for many of you. But for me as a novice
it is not easy.

So far, here is what I have using Commons Math;

import org.apache.commons.math3.distribution.PoissonDistribution;

public class poissonDistribution
       public static void main(String[] args)
              PoissonDistribution ambulanceDistribution = new PoissonDistribution(9);

The console output is; "org.apache.commons.math3.distribution.PoissonDistribution@27716f4"

I did try and take matters into my own hands and write the equation out (shown below). But
I have a very strong preference to use a method provided by Commons Math. I am much more confident
in Commons Math than my own abilities.

The following is my code. It works in a fashion, but I am not confident in it. Shown below
is what I am currently using - but prefer to avoid using this;
import java.lang.Math;
public class PoissonExperiment1
       public static void main(String[] args)
              // c is the average number of calls per hour. This is a variable that is
              // derived from your database.
              double c = 9.0;
              // k is the number of expected calls we want to determine the probability
              int k = 1;
              while (k <= 20)
                     int factorialResult = 1;
                     for (int i = 1; i <= k; i++)
                           factorialResult = factorialResult * i;
                     double term1 = (Math.pow(Math.E, -c));
                     double term2 = Math.pow(c, k);
                     double numerator = term1 * term2;
                     double answer = numerator / factorialResult;
                     System.out.format("%10.3f:%n ", answer);

Thank you for your consideration and time,

David Kulpanowski
Database Analyst
Lee County Public Safety
PO Box 398
Fort Myers, FL 33902

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