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Subject: Re: [scxml] How to retrieve the transition target in a custom action
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Le 21 sept. 2010 =E0 00:12, Rahul Akolkar a =E9crit :

> <snip/>
>=20
> I believe you mean a transition thats not a stay nor self transition,
> since the only way a custom action will ever execute is if some
> transiton is being followed (in order for SCXML executable content to
> execute).

Thank you Rahul for your answer.
Indeed I want to know wether I'm in a stay or self transition. I confirm =
that my custom action is within a transition (or onentry/onexit).
>=20
> There isn't a direct way to access information about the transition
> target. I imagine your custom action is within a transition element.
> If so, you could walk up the SCXML object model and check whether the
> parent transition has a target attribute and whether it is the parent
> state id itself.

How can you do this from within a custom action?

> It may also be possible to infer whether a (non-stay)
> transition is being followed and what the target is, by using a
> suitable SCXMLListener impl.
>=20
> For long computations, you should consider using the external
> communications module (either <send> or <invoke>) to send an event to
> (or invoke) some external process which manages the computation and
> fires a completion event on the state machine when done.

I quickly looked at the invoke examples provided in SCXML tests and they =
seem less appropriate than using custom actions, which make the XML file =
more readable IMHO.

>=20
> -Rahul
>=20
>=20
>> I need this info to know if it is possible to launch a long =
computation in a different thread:
>> - if there is a transition target, the state machine will go to the =
new state and my computation will be started in one state and continue =
in another one, which I want to avoid.
>> - if there is no transition target, it means that my computation is =
performed within the original state (internal transition) and I can use =
my computation without fearing an undetermined state machine.
>>=20
>> Kind regards,
>>=20
>> Ben
>=20
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>=20
>=20


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