Mailing-List: contact user-help@commons.apache.org; run by ezmlm
Precedence: bulk
Reply-To: "Jakarta Commons Users List" <user@commons.apache.org>
Received-SPF: pass (athena.apache.org: domain of pmanabe@gmail.com designates
 66.249.82.227 as permitted sender)
DomainKey-Signature: a=rsa-sha1; c=nofws;
        d=gmail.com; s=gamma;
        h=message-id:date:from:to:subject:in-reply-to:mime-version:content-type:references;
        b=Er6cRzD6jIH2R2vxWvd5IIxIaTxitRccs0skukpiC1IeguZjgKbkOfkpQ342n2vAUkgnUOdteeqba9Zu0pMSceRpjZlw6YSjL64L7KPHvkjvUZiHmh4kNK9Zm2L8il3NteTZOhTnrgF0c/LqhjKsER/WNhSkD6ODtAdvyv4zvL0=
Message-ID: <37f476ab0801170654m6d56c6b7mcc28636a030a2419@mail.gmail.com>
Date: Thu, 17 Jan 2008 12:54:54 -0200
From: "Paulo Manabe" <pmanabe@gmail.com>
To: "Jakarta Commons Users List" <user@commons.apache.org>
Subject: Re: Fileupload like tomcat
In-Reply-To: <37f476ab0801170500j6d3170cfg802e29003ef1168c@mail.gmail.com>
MIME-Version: 1.0
Content-Type: multipart/alternative;
	boundary="----=_Part_14342_6830716.1200581694038"
References: <37f476ab0801161321t3682bf4ds214e078de9648e60@mail.gmail.com>
	 <30f92e840801161844m24c9ff7cxc23abd62f216d0c5@mail.gmail.com>
	 <37f476ab0801170500j6d3170cfg802e29003ef1168c@mail.gmail.com>

------=_Part_14342_6830716.1200581694038
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

let me try... if you see in the tomcat manager page, you are able to do 2
kind of deployments. The first if you will deploy th war file located on
server and the second if you will deploy a war file from the client side
(You will click the button browse... and them choose the war file...). What
I need to do is like the first. I know where the file is on server and I
would like to read it and them save in the database..... I couldn't
understand
this sintaxe file://C:\some dir\some folder, and how can I read this file
using this path......

Best Regards


> 2008/1/17, Anas Mughal <anasmughal@gmail.com>:
> >
> > Honestly, you are not clear.  Let me try to help.
> >
> > If you are trying to do a file upload to a Tomcat application, consider
> > using commons FileUpload:
> >
> > http://commons.apache.org/fileupload/
> >
> >
> > After the file gets uploaded, your application can save it anywhere that
> > the
> > Tomcat application has write access to.
> >
> >
> > Hope this helps...
> >
> > --
> > Anas Mughal
> >
> >
> >
> >
> >
> > On Jan 16, 2008 4:21 PM, Paulo Manabe <pmanabe@gmail.com> wrote:
> >
> > > I'm trying to upload a file from the server side like tomcat
> > deployment.
> > > How
> > > is it? I can create a simple FileInputStream() object declaring the
> > full
> > > path? One doubt is if is posible to tomcat see another computer in the
> > LAN
> > > network and access there files and upload them...
> > >
> > > Thanks in advance.
> > >
> >
> >
> >
> > --
> > Anas Mughal
> >
>
>

------=_Part_14342_6830716.1200581694038--