Is it correct an approach like:
[CODE]
//(...)
FtpClient myc = new FtpClient( ); //init ftpclient
myc.connect( "proxy.acme.ch", 21 ); //connect to server
myc.login( "far-username@ftp.far-server.ch proxy_tech_userename", "far_password" ); //login
if( myc.getReplyCode() == FtpReply.CODE_332 ){ //check if reply is 332
	myc.sendCommand( "proxy_tech_password" );
}
//(...)
[/CODE]
Can this be a possible solution? Sorry that I ask but I actually can't test... ;-)
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On Fri, 3 Feb 2006 08:58:44 +0100
"e.dominguez" <e.dominguez@ticino.com> wrote:
> Hi.
> I trying to connect to an ftp server through a proxy by a customer.
> the enterprise has a proxy server, so for the connection I have received this 'connection example' (it's in german but i think is understandable):
> 
> Sobald Sie die UserID und das Passwort für den Technical Account erhaltet haben, müssen Sie folgende Syntax anwenden:
> (Beispiel basiert auf W32 FTP-Client).
>  
> c:\>ftp proxy.acme.ch
> Verbindung mit proxy.acme.ch wurde hergestellt.
> 220 Blue Coat FTP Service
> Benutzer (proxy.acme.ch:(none)): far-username@ftp.far-server.ch proxy_tech_userename
> 331 Enter password.
> Kennwort: far_password
> 332 Enter proxy password.
> Kennwort: proxy_tech_password
> Hier nochmal die technische Syntax, die angewendet werden soll:
> Usage: USER username@hostname proxyusername
>        PASS password
>        ACCT proxypassword
> 
> How can i pass the second password (332/ACCT) as connection property for my pgm?
> 
> Thanx. Best regards. e.dominguez


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