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From: "Schalk" <schalk@volume4.co.za>
To: "'Jakarta Commons Users List'" <commons-user@jakarta.apache.org>
Subject: RE: [FileUpload] File Separator question
Date: Thu, 24 Jul 2003 08:34:32 +0200
Message-ID: <002801c351ad$a78d4030$0100a8c0@DELL530>
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Rhino

=20

I use the bit of code below to determine the actual filename of the file
being uploaded:

=20

StringTokenizer tokenizer =3D new StringTokenizer(fileName, "\\, :, /");


            int amount =3D tokenizer.countTokens();            =20

            for (int i =3D 0; i < amount -1; i++) {

                tokenizer.nextToken();       =20

            }              =20

            String currentFile =3D tokenizer.nextToken();

=20

I then store the folder to which I want the file  to be written as a =
public
String at the top of my servlet i.e.

public String serverFolder =3D
"/var/www/vhosts/nexroot/webapps/Nexroot/ssl/FTP/files/";

=20

Then write the file to disk as follows:

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File diskFile =3D new File(serverFolder, currentFile);

                       =20

            item.write(diskFile);          =20

           =20

            item.delete();

=20

Hope this helps you out.

=20

Kind Regards

Schalk Neethling

Volume4.Development.Multimedia.Branding

emotionalize.conceptualize.visualize.realize

Tel: +27125468436

Fax: +27125468436

email:schalk@volume4.co.za

web: www.volume4.co.za

=20

-----Original Message-----
From: Rhino [mailto:rhino1@sympatico.ca]=20
Sent: Thursday, July 24, 2003 1:36 AM
To: commons-user
Subject: [FileUpload] File Separator question

=20

I need some help to get my FileUpload servlet to work "cross-platform".

=20

It works okay when uploading a file from a Windows machine to a Windows
server but it misbehaves when I try to upload a file from a Windows =
machine
to a Linux server; it isn't setting the file name properly.

=20

In a Windows->Windows scenario, the file I am uploading is something =
like
C:\original-dir\original-subdir\my.file. My servlet uses
lastIndexOf(File.separator) to find the file name proper, e.g. my.file, =
and
then concatenates it to the end of the path where I want the file stored =
in
the server, e.g. C:\stored-dir\stored-subdir\my.file. The servlet saves =
the
file successfully and when I look at the C:\stored-dir\stored-subdir
directory in my file system, the file name is my.file, exactly as I =
want.

=20

In a Windows->Linux scenario (i.e. uploading a Windows file to a Linux
server), the servlet stores the file in the desired directory but it has =
its
full original name, e.g. C:\original-dir\original-subdir\my.file, not =
just
my.file. That means that the full file name of the uploaded file is
something along the lines of
/home/rhino/tomcat4/webapps/FileUploadServlet/SDAC-upload/C:\\original-di=
r\\
original-subdir\\my.file. Clearly, that is not desireable; I want the
uploaded file name to be
/home/rhino/tomcat4/webapps/FileUploadServlet/SDAC-upload/my.file.

=20

It seems clear to me that the file separator is the problem here. When =
the
servlet is running in Linux, it determines the value of file.separator =
to be
'/' while the file being uploaded is in Windows which has a =
file.separator
of '\'. The lastIndexOf(File.separator) therefore never finds the file =
name
proper and saves the entire path in the name, not just the last bit.

=20

I'm not so sure what to do about it. Do I need to have my code determine =
the
OS from which it is getting the file which is being uploaded or is there
some other technique I need to use? How would I determine the OS from =
which
I'm uploading? I know that I can get the OS of the server from the Java
system property "os.name" but how do I get the OS which is the source of =
the
file upload?

=20

I am running Tomcat 4.1.24 on both the Windows XP and Linux boxes. The =
Linux
box is running Mandrake 9.1.

=20


Rhino
---
rhino1 AT sympatico DOT ca
"If you want the best seat in the house, you'll have to move the cat."


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