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From "Martin Cooper" <mart...@apache.org>
Subject Re: FileUpload
Date Wed, 12 Feb 2003 14:27:16 GMT

"Schalk" <schalk@volume4.co.za> wrote in message
news:003301c2d281$dca4fed0$0100a8c0@ServerMAIN...
> M.Assunta
>
> Attached is a fileUpload servlet that should solve your problem.

No, your servlet will not solve the problem. The issue is that once the
request input stream has been parsed once, it is gone. There isn't a way to
re-read that stream, so there isn't a way to make parseRequest() work a
second time.

--
Martin Cooper


>
> Kind Regards 
> Schalk Neethling 
> Volume4.Development.Multimedia.Branding
> .emotionalize.conceptualize.visualize.realize
> Tel: +27125468436
> Fax: +27125468436
> email: schalk@volume4.co.za
> url: www.volume4.co.za
> ----- Original Message -----
> From: "Apollonio Maria assunta" <m.apollonio@tno.it>
> To: <commons-user@jakarta.apache.org>
> Sent: Wednesday, February 12, 2003 11:27 AM
> Subject: FileUpload
>
>
> Hi,
>
> I see a very strange behaviour of fileUpload component.
> I need to execute the " fileUpload.parseRequest(request)" twice, but at
the
> second round it returns empty List of items.
> Can you help me?
> Thanks.
> M.Assunta
>
>
>


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