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From "Kevin Childs (JIRA)" <j...@apache.org>
Subject [jira] Created: (MATH-371) PearsonsCorrelation.getCorrelationPValues() precision limited by machine epsilon
Date Thu, 13 May 2010 19:50:42 GMT
```PearsonsCorrelation.getCorrelationPValues() precision limited by machine epsilon
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Key: MATH-371
URL: https://issues.apache.org/jira/browse/MATH-371
Project: Commons Math
Issue Type: Bug
Affects Versions: 2.0
Reporter: Kevin Childs

Similar to the issue described in MATH-201, using PearsonsCorrelation.getCorrelationPValues()
with many treatments results in p-values that are continuous down to 2.2e-16 but that drop
to 0 after that.

In MATH-201, the problem was described as such:
> So in essence, the p-value returned by TTestImpl.tTest() is:
>
> 1.0 - (cumulativeProbability(t) - cumulativeProbabily(-t))
>
> For large-ish t-statistics, cumulativeProbabilty(-t) can get quite small, and cumulativeProbabilty(t)
can get very close to 1.0. When
> cumulativeProbability(-t) is less than the machine epsilon, we get p-values equal to
zero because:
>
> 1.0 - 1.0 + 0.0 = 0.0

The solution in MATH-201 was to modify the p-value calculation to this:
> p = 2.0 * cumulativeProbability(-t)

Here, the problem is similar.  From PearsonsCorrelation.getCorrelationPValues():
p = 2 * (1 - tDistribution.cumulativeProbability(t));

Directly calculating the p-value using identical code as PearsonsCorrelation.getCorrelationPValues(),
but with the following change seems to solve the problem:
p = 2 * (tDistribution.cumulativeProbability(-t));

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