I hope you put the xsl:param at top level of your xslt?? Otherwise it
will not work.
<xsl:param> does have a scope so you should not declare that <xsl:param>
for instance inside a <xsl:template match=""> if you pass it on from
your sitemap.
First show me how (read where) you declared the parameter filename in
your xslt.
Cheers,
Robby Pelssers
-----Original Message-----
From: Jean-Bonneau [mailto:rg1693@gmail.com]
Sent: Wednesday, July 22, 2009 11:51 AM
To: users@cocoon.apache.org
Subject: retrieving requested filename in XSL
Hello,
I want to ouput the filename requested in the URL in an XSL stylesheet
(e.g.
get "toolz" from http://server/cocoon/page-toolz), but it doesn't work.
Here is the involved part of the sitemap:
...
<map:match pattern="page-*">
<map:generate src="content/pages/{1}.xml"/>
<map:transform src="style/xsl/page2html.xsl">
<map:parameter name="filename" value="{1}" />
</map:transform>
<map:serialize type="xhtml" />
</map:match>
...
Then, the xsl style/xsl/page2html.xsl markup:
...
<xsl:param name="filename" />
<xsl:attribute name="href">
doc-<xsl:value-of select="$filename" />.pdf
</xsl:attribute>
Version PDF
But this always print doc-.pdf
I tried <xsl:variable name="filename" /> instead of <xsl:param
name="filename" />, but it doesn't work either.
Can you help me gess why isn't the parameter working ?
Thanks.
Rodolphe GOHARD.
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