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From Jakob Praher <jpra...@yahoo.de>
Subject Re: How to get the Browser URL within XSL?
Date Tue, 13 May 2003 14:38:28 GMT
use the following:

<map:transform type="xslt" ...>

   <map:param name="request-uri" value="{request:requestURI}" />

</map:transform>

@see samples/modules/sitemap.xmap

-- Jakob

Am Die, 2003-05-13 um 15.42 schrieb Hubert Holtz:
> Hy all,
> 
> First of all I do not know if this is a pure xsl or cocoon question so i mail it to both
lists.
> 
> I know I can access the request parameters of the url in xsl using the xsl-with-parameters
type in my sitemap,
> but how can I get the whole URL string in xsl.
> 
> The reason why I need to get this, is that I have the following URL structure:
> 
> http://www.somwhere.de/test/program.html?id=300&lang=ger
> 
> and I want to change the lang value to another value (eng i.e.) by clicking on my flag
symbol, the problem is that I don't know
> the sitename in front of .html, because I just want to change the lang parameter the
rest should be the same,
> depending on the last requested url (or is it possible to get this value inside xsl?)
!
> 
> I'm using Cocoon 2.03 on tomcat4.1.
> 
> Any help is welcome.
> 
> Regards, Steve
> 
> 
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