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From "Per Kreipke" <...@onclave.com>
Subject RE: XSP bug: can get generate() to skip elements using java 'if's
Date Mon, 09 Sep 2002 22:48:27 GMT
Note: in xsp.xsl, the topmost non-xsp element is handled specially but this
error still occurs if you nest like this:

<page>
  <foo>
    <xsp:logic>if (...) {
      <xsp:attribute...>
      }
      else
      {
    </xsp:logic>
    ...
    <xsp:logic>
    }
    </xsp:logic>
  </foo>
</page>

The culprit is the <xsp:attribute>. If I comment it out, the error doesn't
happen.

Per


> The following XSP snippet will cause an ArrayIndexOutOfBoundsException in
> Cocoon 2.0.3 because the start of the outer element is never
> emitted to the
> SAX stream.
>
> XSP Snippet:
>
>
> <xsp:page ....>
>
>  <page>
>   <xsp:logic>
>     if (!request.isUserInRole("root"))
>     {
>       <xsp:attribute name="security-error">Not authorized</xsp:attribute>
>     }
>     else
>     {
>   </xsp:logic
>
>     <!-- Build the page if authorized -->
>     <content />
>
>   <xsp:logic>
>     }
>   </xsp:logic>
>  </page>
>
> </xsp:page>
>
>
>
>
> Generated Java code:
>
> if (!request.isUserInRole("root"))
> {
>   xspAttr.addAttribute("", "security-error", "security-error",
> "CDATA", "Not
> authorized");
> }
> else
> {
>   this.contentHandler.startElement("", "page", "page", xspAttr);
>   xspAttr.clear();
>
> }
>
> this.contentHandler.endElement("", "page", "page");
>
>
>
> E.g. the start code for <page> isn't emitted. And I can't find a
> workaround:
> neither emitting characters or another element inside the 'if' makes it
> emit.
>
> Per
>
>
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