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From "Martin Mauri" <mma...@profesi.com.ar>
Subject Re: XSL question
Date Mon, 25 Mar 2002 14:36:08 GMT
Dear Alexandre,

Yes, I already know how to use params, but the point here is that I need to
pass the param from an outside source, say, the xml page that uses this
stylesheet ok? I don't know if I'm being clear, but that's my problem.
thanks!

----- Original Message -----
From: "Alexandre Victoor" <avictoor@prisma-presse.com>
To: <cocoon-users@xml.apache.org>
Sent: Monday, March 25, 2002 11:32 AM
Subject: Re: XSL question


> Hi,
> you need to declare your parameter at the beginiing of the stylesheet :
>
> <xsl:param name="yourparam"/>
> ....
> <xsl:template match="/">
> ....
>
> Then in the body of your stylesheet, $yourparam  gives you the value of
the
> parameter.
>
> Good luck
> Alex
>
>
>
>
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