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From Ludovic Maitre <Ludovic.Mai...@sophia.inria.fr>
Subject xinclude before xslt, how retrieve the url ?
Date Mon, 30 Jul 2001 17:55:36 GMT
Hello Cocoon users,

I want to include some files in a xml file in Cocoon 1.8.2.
For example this index.xml :

<?xml version="1.0"?>
<?xml-stylesheet href="index.xsl" type="text/xsl"?>

<?cocoon-process type="xinclude"?>
<?cocoon-process type="xslt"?>

<page xmlns:xinclude="http://www.w3.org/1999/XML/xinclude" >
<xinclude:include xinclude:parse="xml" xinclude:href="page1.xml"/>
<xinclude:include xinclude:parse="xml" xinclude:href="page2.xml"/>
<xinclude:include xinclude:parse="xml" xinclude:href="page3.xml"/>
</page>

and i want to apply a xsl who transform all these includes in a summary,
a list of all the title elements contained in the included XML pages
with 
an hyperlink to these pages. 

Anybody know how i can retrieve the url of the included files from
index.xsl 
for generate a <a href> tag ? 
[i have test with the document() function of XSLT, for obtaining the
URI-basename
of the nodes that i traverse but i haven't succedeed to obtain the url
of the nodes]

Obviously, the purpose is to make a menu, perhaps it's not the good way 
if this is the case i appreciate any suggestion.

Thanks per advance and good evening (or day), 

-- 
 Ludovic.Maitre@sophia.inria.fr

 INRIA - 2004 route des lucioles - BP 93    Tel: (33/0) 4 92 38 50 41
 06902   SOPHIA-ANTIPOLIS cedex (France)    Fax: (33/0) 4 92 38 76 02

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