cocoon-users mailing list archives

Site index · List index
Message view « Date » · « Thread »
Top « Date » · « Thread »
From Johannes Koch <k...@pixelpark.com>
Subject Re: How to get the URI of an XML document in an XSL stylesheet?
Date Tue, 09 Jan 2001 15:07:28 GMT
"Dr. Uwe Meyer-Gruhl" schrieb:
> 
> Hi,
> 
[...]
> So I guess I have to find a way of generating the source document file
> name from the stylesheet prepended to the "?aspekt=" part but have been
> unlucky at finding out how. Is there a function or pre-defined variable
> in Cocoon or Xalan or a method for that in standard XSLT?

You can get the XML file URI using XSP
(<xsp:expr>request.getRequestURI()</xsp:expr>)

-- 
Johannes Koch  . IT Developer
Pixelpark AG   . http://www.pixelpark.com
Rotherstra├če 8 . 10553 Berlin  .  Germany
phone: +49 30 5058 - 1288  .  fax: - 1355

Mime
View raw message