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From Rajesh Aravindakshan <aravindraj...@yahoo.com>
Subject Custom Generator Parsing issue
Date Fri, 15 Apr 2005 18:32:05 GMT
Sorry. I know this is not the right forum. I tried in
users forum and nobody gave me a good answer. Thought
some of you geniusus here would have an answer. 
Thank you.

Hi,
I am able to get an xml output from a custom
generator.The custom generator creates an xml from an 

http request. The http request can replaced by a xml
string as an example. It displays in the browser as
XML tree. But,I am not able to transform the output
with an xsl stylesheet. It displays the data as text. 
What am I doing wrong. Please help. Thank you.


Here is my sitemap:
<map:match pattern="mygenerator.xml">
 <map:generate type="mygenerator">
   <map:parameter name="use-request-parameters"
value="true"/>
 </map:generate>
 <map:transform src="stylesheets/test.xsl"/>
 <map:serialize type="html"/>
</map:match>
------------------------------
Here is my custom generator code.
(Sorry for the long code)

public class MyGenerator extends AbstractGenerator {

  Request request = null;
  Enumeration paramNames = null;


public void setup(SourceResolver resolver, Map
OjectModel,String src, Parameters par)
           throws ProcessingException, SAXException,
IOException {

public void generate () throws IOException,
SAXException, ProcessingException {
try{
 SAXParserFactory spf =
SAXParserFactory.newInstance();
 spf.setValidating(false);
 SAXParser saxParser = spf.newSAXParser();
 // create an XML reader
 XMLReader reader = saxParser.getXMLReader();
  
 String message = getResponse();
 /*this message can be a xml string*/

 reader.setContentHandler(super.xmlConsumer);
 reader.parse(new InputSource(new
 StringReader(message)));
} catch(Exception e){}
/*XMLReader xmlreader =
SAXReaderFactory.createXMLReader();
xmlreader.setContentHandler(super.xmlConsumer);
InputSource source = new InputSource(new
StringReader(message));
xmlreader.parse(source);*/
}


private String getResponse() {
        String xmlResponse = new String();
        String inputLine;

    String urlstr =
"http://srv/cgi-bin/cgiip.exe/getxml.p";;
    
    String str = "?";

   try{
     URL url = new URL(urlstr);
     URLConnection  connection = url.openConnection();
     BufferedReader in = new BufferedReader(new
     InputStreamReader(connection.getInputStream()));

     while ((inputLine = in.readLine()) != null) {
      if (xmlResponse==null) xmlResponse = 
                     new String();
      xmlResponse = xmlResponse + inputLine;
     } // while

     in.close();
   } catch(Exception e){
       System.out.println("ERROR WHILE CONNECTION: " +
    e.toString());
    return 
       "<response><status>ERROR</status></response>";
     }

  return xmlResponse;
  }

Thanks in advance.
Rajesh Aravindakshan

Regards,
Rajesh Aravindakshan

Regards,
Rajesh Aravindakshan


		
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