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From Stephan Michels <step...@apache.org>
Subject Re: [PROPOSAL] Sources, the next generation RE: Speedup *DirectoryGenerator
Date Sat, 22 Jun 2002 20:52:52 GMT


On Fri, 21 Jun 2002, Jens Lorenz wrote:

> ----- Original Message -----
> From: "Stephan Michels" <stephan@apache.org>
> To: "cocoon-dev" <cocoon-dev@xml.apache.org>
> Sent: Friday, June 21, 2002 3:54 PM
> Subject: RE: [PROPOSAL] Sources, the next generation RE: Speedup
> *DirectoryGenerator
>
> <snip/>
>
> >
> > I think it should work like this:
> >
> > Source source = resolver.resolveURI("dav://mydir/mydir2/");
> > if (source instanceof TraversableSource) {
> >     TraversableSource tsource = (TraversableSource) source;
> >
> >     Source parent = resolver.resolveURI(tsource.getParentSource());
> >     Source child = resolver.resolveURI(tsource.getChildSource(0));
> > }
> >
>
> Just wanted to mention, that there document stores, where one
> TraversableSource can have multiple ParentSources. For example
> unix hardlinks

I think a link, and the document, which the link points to, has only one
parent.


/dir/link -> /file
  parent: /dir

/file
  parent: /


> document managment systems with some sort of collections.
> and one document being in more than one collection.

That can be.

> Document
> having meaning of a single file and Collection having the
> meaning of folder which has files.

Thats the reason for:
  TranverableSource:
    boolean isCollection()

> (Yes, this really sets your mind twisting, if you have to deal with
> stuff like this)
>
> So there should be a convenience method named getParentSource()
> (or similar) which just returns the first parent (most of the
> times there will be only one) and another way of accessing the
> other parents.

I would you agree, if there wasn't the problem of meaning of
'traversable'. If a source has more than one parent, how would
you tranverse such a trajectory?

Difficult ;-)

Thanks for your comment, Stephan Michels.


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