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From Kaushal Shriyan <>
Subject cqlsh ValueError: Don't know how to parse type string
Date Tue, 19 May 2015 07:44:05 GMT

I am running cassandra version 1.2.19 and cqlsh version 3.1.8 in my setup

cqlsh:apprepo> select * from test_proxy_revisions_r21 limit 10 ;
Traceback (most recent call last):
  File "./cqlsh", line 1039, in perform_statement_untraced
    self.cursor.execute(statement, decoder=decoder)
  File "./../lib/",
line 81, in execute
    return self.process_execution_results(response, decoder=decoder)
  File "./../lib/",
line 116, in process_execution_results
  File "./../lib/",
line 97, in get_metadata_info
    name, nbytes, vtype, ctype = self.get_column_metadata(colid)
  File "./../lib/",
line 104, in get_column_metadata
    return self.decoder.decode_metadata_and_type(column_id)
  File "./../lib/",
line 40, in decode_metadata_and_type
    valdtype = cqltypes.lookup_casstype(validator)
  File "./../lib/",
line 145, in lookup_casstype
    raise ValueError("Don't know how to parse type string %r: %s" %
(casstype, e))
ValueError: Don't know how to parse type string
weird characters '=>org.apache.cassandra.db.marshal.UTF8Type)' at end

Any clue?



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