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From 魏金仙 <>
Subject Re:Re: probability of node receiving (not be responsible for) the request
Date Mon, 06 Dec 2010 10:26:08 GMT
thank you.
but I mean the probability of a node to receive the request not process it eventually .

At 2010-12-06 00:56:58,"Brandon Williams" <> wrote:

2010/12/5 魏金仙<>
  If a particular client send 5 requests to a 6-node cluster, then the probability of each
node receiving(not be responsible for) the first request is 1/6.

Assuming RF=1 and RandomPartitioner.
Assume that node1 received the 1st request, will node1 receive the 2nd request, the 3rd one,
the 4th one and the 5th one with high probability or 1/6?
thanks for your time.

1/6th with RandomPartitioner, something much higher with OrderPreservingPartitioner.

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