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From: =?UTF-8?Q?Utku_Can_Top=C3=A7u?= <utku@topcu.gen.tr>
Date: Mon, 7 Jun 2010 18:04:08 +0200
Message-ID: <AANLkTiljIw-2VUYvAnQlpnMPvPAyXUHD-YfvcvbilBB6@mail.gmail.com>
Subject: Getting keys in a range sorted with respect to last access time
To: user@cassandra.apache.org
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Hey All,

First of all I'll start with some questions on the default behavior of
get_range_slices method defined in the thrift API.

Given a keyrange with start-key "kstart" and end-key "kend", assuming
kstart<kend;
* Is it true that I'll get the range [kstart,kend) (kstart inclusive, kend
exclusive)?
* What's the default order of the rows in the result list? (assuming I am
using an OPP)
* (How) can we reverse the sorting order?
* What would be the behavior in the case kstart>kend? Will I get an empty
result list?

Secondly, I have use case where I need to access the latest updated rows?
How can this be possible? Writing a new partitioner?

Best Regards,
Utku

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Hey All,<br><br>First of all I&#39;ll start with some questions on the defa=
ult behavior of get_range_slices method defined in the thrift API.<br><br>G=
iven a keyrange with start-key &quot;kstart&quot; and end-key &quot;kend&qu=
ot;, assuming kstart&lt;kend; <br>

* Is it true that I&#39;ll get the range [kstart,kend) (kstart inclusive, k=
end exclusive)?<br>* What&#39;s the default order of the rows in the result=
 list? (assuming I am using an OPP)<br>* (How) can we reverse the sorting o=
rder?<br>

* What would be the behavior in the case kstart&gt;kend? Will I get an empt=
y result list?<br><br>Secondly, I have use case where I need to access the =
latest updated rows? How can this be possible? Writing a new partitioner?<b=
r>

<br>Best Regards,<br>Utku<br>

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