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From "DEPREZ Arnaud AWL-IT" <arnaud.dep...@atos.net>
Subject RE: Naming your file with org.apache.camel.file.name
Date Tue, 04 Sep 2012 12:38:39 GMT
I don't see where you call the method sendTo(...).
If you don't call it, Camel will put the Exchange ID as the name of your file.


Arnaud Deprez
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-----Original Message-----
From: Saurabh [mailto:computerfresher@gmail.com]
Sent: mardi 4 septembre 2012 13:42
To: users@camel.apache.org
Subject: Re: Naming your file with org.apache.camel.file.name


Hi Friends,

I am working on a small spike in which my task is to pick an xml from a
directory, put it on jms queue and save the xml to some other directory.

This is the code snapshot, this is after I converted the file contents in to
a string.

private static final String URI = "activemq://queue:test.MyQueue"  ;

protected void sendTo(String uri,String message) throws Exception {
                ProducerTemplate producerTemplate = camelContext.createProducerTemplate();
                Exchange exchange = new DefaultExchange(camelContext,
ExchangePattern.InOut);
                exchange.getIn().setBody(message);
                Message camelMessage = exchange.getIn();
                camelMessage.setHeader(Exchange.FILE_NAME, "testmesage");
                System.out.println(exchange.getExchangeId());
                System.out.println(exchange.getIn().getMessageId());

                producerTemplate.send(uri, exchange);
                Thread.sleep(1000);
        }

and camel route is
    <route>
        <from uri="jms:test.MyQueue"/>
        <to uri="file://target/test?noop=true/>
    </route>

The file appears in target but with name
ID-localhost-46447-1346755756577-0-2-2-1-1

and not "testmessage" as I specified.

hope I am clear
Please help

Thanks in advance
Saurabh






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