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Date: Wed, 23 Nov 2011 05:18:22 -0800 (PST)
From: majiedahamed <majied.bangar@cognizant.com>
To: users@camel.apache.org
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Subject: Re: Catch camel exception in java code
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The camel version is 2.4

1)the original code is 
+++++++++++++++
<onException useOriginalMessage="true">			

<exception>org.apache.camel.processor.validation.SchemaValidationException</exception>	
 <exception>org.xml.sax.SAXParseException</exception>	   
 <exception>org.apache.camel.ValidationException</exception>
 
 <exception>java.lang.Exception</exception>		
 <redeliveryPolicy maximumRedeliveries="0" />				
 <handled>
  <constant>true</constant>
 </handled>
  <to
  uri="log:xml? 
level=INFO&amp;showException=true&amp;showCaughtException=true&amp;showStackTrace=true"
/>
  <to uri="file:{{retry_loc}}" />
  <to uri="bean:myBean"/>
</onException>

2) My class is 

public class MyBean {
	
	public void doSomething(Object body, Exception cause) { 
		cause.printStackTrace();
	}

}

3)Bean decleration is <bean id="myBean" class="MyBean"></bean> 

Please suggest should i use parameter to the below and try ?

<to uri="bean:myBean?methodName=doSomething"/>


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