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From Claus Ibsen <claus.ib...@gmail.com>
Subject Re: How do I get the exception information that is caught in Spring DSL routes?
Date Fri, 09 Sep 2011 10:15:58 GMT
On Thu, Sep 8, 2011 at 7:01 PM, Robert J. Liguori <camel@gliesian.com> wrote:
> How do I get the exception information that is caught in Spring DSL
> routes?
>
> For, example, when I'm using the validation component, the exception
> routes the invalid XML to the specified endpoint:
>
>            ...
>           <doCatch>
>
> <exception>org.apache.camel.ValidationException</exception>
>                <to uri="mock:invalid"/>
>            </doCatch>
>            ...
>
> That's cool, but I want to see what the exception was... how do I get
> to it?  Note that I'm new to Spring and Camel.
>

The exception is stored as a property on the Exchange.
In java code its like this:

Exception cause = exchange.getProperty(Exchange.EXCEPTION_CAUGHT,
Exception.class);




> Thanks,
> Robert
>



-- 
Claus Ibsen
-----------------
FuseSource
Email: cibsen@fusesource.com
Web: http://fusesource.com
Twitter: davsclaus, fusenews
Blog: http://davsclaus.blogspot.com/
Author of Camel in Action: http://www.manning.com/ibsen/

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