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From: =?UTF-8?Q?Andr=C3=A8?= <morpheusandre@web.de>
To: users@camel.apache.org
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Subject: Re: Is it possible to propagate an exception to the parent route?
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i=C2=B4m trying that by wrapping an exception in a RuntimeCamelException an=
d the
exception consumer is dewraping and throwing it again,=20
but at the producer i=C2=B4m getting a nullpointer, so somewhere i=C2=B4m l=
oosing the
exception, cause i should get the runtimecamelException ...

any ideas ?=20
(thx, your answers already helped that much.. )
(Exception producer)
=09<from
=09=09=09
uri=3D"activemq:topic:services.global.xacml.authzRequests?transferException=
=3Dtrue"
/>
=09=09=09<log message=3D" Xacml request consumed" />
=09=09=09<doTry>
=09=09=09=09<to uri=3D"bean:pdp" />
=09=09=09=09<doCatch>
=09=09=09=09=09<exception>org.jboss.security.xacml.sunxacml.ParsingExceptio=
n
=09=09=09=09=09</exception>
=09=09=09=09=09<process ref=3D"ExceptionWrapper"/>
=09=09=09=09</doCatch>
=09=09=09</doTry>
(Wrapper)
=09public void process(Exchange exchange) throws Exception {
=09=09
=09=09Exception e =3D exchange.getException();
=09=09RuntimeCamelException wrapper =3D new RuntimeCamelException(e.getCaus=
e());
=09=09wrapper.setStackTrace(e.getStackTrace());
=09=09exchange.setException(wrapper);

=09}


(Exception consumer)
=09=09=09<from uri=3D"direct:AuthzService" />
=09=09=09<to uri=3D"bean:isAuthZBlocked?method=3DcheckRequest" />
=09=09=09<doTry>
=09=09=09=09<to
=09=09=09=09
uri=3D"activemq:topic:services.global.xacml.authzRequests?transferException=
=3Dtrue"
/>
=09=09=09=09<doCatch>
=09=09=09=09=09<exception>org.apache.camel.RuntimeCamelException</exception=
>
=09=09=09=09=09<process ref=3D"ExceptionDeWrapper" />
=09=09=09=09</doCatch>
=09=09=09</doTry>

(DeWrapper)
=09public void process(Exchange exchange) throws Exception {
=09=09throw exchange.getException();=20
}


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