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From "Dragisa Krsmanovic" <dkrsmano...@plos.org>
Subject Re: Message blocks route until all redelivery attempts are exhausted
Date Mon, 05 Apr 2010 17:22:27 GMT
Yes, but this only increases number of messages that are needed to
"block" the route. What if I have thousands of messages and somewhere
between 1 and 1000 can fail ? I don't want "good" messages to wait for
"bad" messages to exhaust their retries.

If I would set concurrentConsumers=2000 that can potentially spawn 2000
threads ? 

I tried a solution by sending bad messages to another, "waiting" route.
But, although good messages are not blocked any more, I still have
similar issue in the "waiting" route where I want to use delay. It can
only delay number of messages that is equal to concurrentConsumers. So,
"bad" messages at the end of the wait queue would wait, not delay() but
(n/concurrentConsumers) * delay() amount of time.



On Sat, 2010-04-03 at 10:10 +0800, Willem Jiang wrote: 
> Hi,
> 
> Can you try to add this option "concurrentConsumers=5" into the seda 
> endpoint's URI?
> By default there is only one thread to consumer the message in the queue.
> 
> Willem
> 
> Dragisa Krsmanovic wrote:
> > I have a route that is configured to re-deliver messages on exception.
> > If there are messages in that queue and one of them fails, all other
> > messages are blocked until all re-delivery attempts are exhausted.
> > 
> > I would like other messages to go through while the ones that failed are
> > waiting for their re-delivery. Message order is not important. What is a
> > good way to do this ?
> > 
> > 
> > The route I tested with looks like this:
> > 
> > from("seda:start")
> >  .onException(Exception.class)
> >    .handled(true)
> >    .redeliverDelay(100)
> >    .maximumRedeliveries(1)
> >    .to("mock:error")
> >  .end()
> >  .process(new TestProcessor())
> >  .to("mock:end");
> > 
> > 
> > 
> > 
> 


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