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From Willem Jiang <willem.ji...@gmail.com>
Subject Re: Not able to invoke webservice using http component
Date Wed, 24 Mar 2010 12:49:22 GMT
Hi,

You can try to use the soap dataformat[1] which is new to Camel 2.3.0.
And you need to download the Camel 2.3.0-SNAPSHOT for it.	

[1]http://camel.apache.org/soap.html

Willem

Harbeer Kadian wrote:
> Hi,
> thanks for the reply.
> I did not changed the input soap message into Document and directly sent it.
> I got the soap message reply in the form of String.
> The reply is as follows
> <?xml version="1.0" encoding="UTF-8"?><soapenv:Envelope
> xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
> xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><soapenv:Body><sayHelloResponse
> xmlns="http://tutorial.com"><sayHelloReturn>Hello Harbeer
> Kadian</sayHelloReturn></sayHelloResponse></soapenv:Body></soapenv:Envelope>
> 
> Now i want to read this output and change it into java objects, just like
> what a webservice client do.
> Do there are any standard api to do this.
> Or I have to use some sort of XQuery or XSLT Transformer to get the soap
> body.
> 
> With Regards
> Harbeer Kadian
> 
> 
> 
> willem.jiang wrote:
>> Yes, if you want to send a request from camel-http endpoint, you just 
>> need put the a Sting, InputStream or HttpEntity into to the message 
>> body, otherwise camel-http endponit may not send right request to the 
>> service.
>>
>> Willem
>>
>> ychawla wrote:
>>> Hi Habeer,
>>> Do you need to do the DOM conversions that you are doing:
>>>
>>> Document input = xmlConverter.toDOMDocument(soapMessage);
>>> exchange.getIn().setBody(input);
>>>
>>> Can't you just set the body to be a string?
>>>
>>> Same with the return message.  That might be tripping something up. 
>>> Also,
>>> are you able to get to your webservice using a browser/basic auth:
>>>
>>> http://localhost:8095/WebServiceTutorial/services/Hello?username=admin&password=admin
>>>
>>> When I was first setting up a web service connection through HTTP, I set
>>> up
>>> a polling folder and result folder and got that working first.  I just
>>> made
>>> the entire soap message in a text editor which it looks like you already
>>> have.  Then you can set up a simple route to test for web service
>>> connectivity:
>>>
>>> <from uri="file:/tmp/input"/>
>>> <to
>>> uri="http://localhost:8095/WebServiceTutorial/services/Hello?username=admin&password=admin"
>>> />
>>> <to uri="file:/tmp/output"/>
>>>
>>> Cheers,
>>> Yogesh
>>>
>>>
>>> Harbeer Kadian wrote:
>>>> Hi,
>>>>
>>>> I deployed a simple webservice on TomCat Server.
>>>> I created following route to access the webservice using apache camel.
>>>>
>>>> from("direct:ProducerUri")
>>>> .to("http://localhost:8095/WebServiceTutorial/services/Hello?username=admin&password=admin");
>>>>
>>>> I created the exchange in the following way
>>>> String soapMessage = "<soapenv:Envelope
>>>> xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\"
>>>> xmlns:tut=\"http://tutorial.com\"><soapenv:Header/><soapenv:Body><tut:sayHello><tut:name>"
>>>>                 + "Harbeer Kadian" +
>>>> "</tut:name></tut:sayHello></soapenv:Body></soapenv:Envelope>";
>>>>             XmlConverter xmlConverter = new XmlConverter();
>>>>             
>>>> Document input = xmlConverter.toDOMDocument(soapMessage);
>>>> exchange.getIn().setBody(input);
>>>> exchange.setPattern(ExchangePattern.InOut);
>>>> //added this line after seeing no soapAction found error on Tom Cat
>>>> Server
>>>> log
>>>> exchange.getIn().setHeader("SOAPAction", "");
>>>> exchange = producerTemplate.send("direct:ProducerUri", exchange);
>>>> Document output = (Document)exchange.getOut().getBody();
>>>> System.out.println(output);
>>>>
>>>> I am getting null as output.
>>>> Also on the tom cat server log, no exception is coming.
>>>>
>>>> I have no idea how to invoke webservice using http component.
>>>> Please help me.
>>>>
>>>> With Regards
>>>> Harbeer Kadian
>>>>
>>>>
>>
>>
> 


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