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Date: Fri, 6 Mar 2015 17:28:16 -0300
Message-ID: 
 <CABpPLBX3Faw_2B0U9VP9pYrX-UBt7WHvpVsJW=0bJXz+nSy2Nw@mail.gmail.com>
Subject: Re: Log xml request file
From: "robertlazarski ." <robertlazarski@gmail.com>
To: "java-user@axis.apache.org" <java-user@axis.apache.org>
Content-Type: text/plain; charset=UTF-8

On Fri, Mar 6, 2015 at 3:29 PM, Oscar Rugama <oscaster@hotmail.com> wrote:
>   So because I have changed the soap header I want to know how exactly the
> soap envelope will go I mean the soap request which is a xml file just to
> compare with the structure I know that should be sent.
>
> For me it is ok if something like system.out.printl(request) and appears in
> the log the all soap request xml file
>
> Does it make sense now?
>
> Thanks your support is her appreciated.
>
> Un saludo,
> Oscar

This may help:

MessageContext messageContext = MessageContext.
getCurrentMessageContext();
String request = messageContext.getEnvelope().toString();

- R

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