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In-Reply-To: <KPEEJKFHNIBMONBHHOGBKEHJCAAA.rmlowe@rmlowe.com>
Subject: RE: Discovering the webapp path.
To: axis-user@ws.apache.org
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 <OF99E47578.0EC9BE9E-ON85256E14.006BDE27-85256E14.006C6F70@mro.com>
From: Junaid.Bhatra@mro.com
Date: Wed, 7 Jan 2004 14:45:19 -0500
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You can try the following:

String realWebInfPath = ctx.getRealPath("/WEB-INF");

This should give you the abolute path to the the /WEB-INF folder assuming
your web app is not packaged up as a .war file (in this case it will return
null). You can then work off there.

- Junaid


             "Robert Lowe"                                                 
             <rmlowe@rmlowe.co                                             
             m>                                                         To 
                                       <axis-user@ws.apache.org>           
             01/07/2004 01:55                                           cc 
             PM                                                            
                                                                   Subject 
                                       RE: Discovering the webapp path.    
             Please respond to                                             
             axis-user@ws.apac                                             
                  he.org                                                   
                                                                           
                                                                           
getResourceAsStream() can be used to load any kind of file from the
classpath, not just .class files. For example, it can be used for image
files or configuration files--useful for loading any kind of resource when
you don't know or care about the nature of the underlying filesystem.

What it *can't* be used for however, is writing or modifying files, so it's
probably not useful to you.

What I've done in the past is include a configuration parameter (e.g. a
servlet init-param) to specify the filesystem location of the webapp
directory. Of course that's one more thing that needs to be configured at
deployment time-- but I'm not aware of a better solution.

Best regards,

Robert Lowe
http://RMLowe.com/


-----Original Message-----
From: Sean Leblanc [mailto:SeanL@insightamerica.com]
Sent: Thursday, January 08, 2004 2:38 AM
To: 'axis-user@ws.apache.org'
Subject: RE: Discovering the webapp path.


user.dir gives me the directory of the tomcat binary directory. I'm not
sure
that will always and forever be the case?

getResourceAsStream() I'm not familiar with. It looks like it's used to
load
classes? Loading classes is actually why I was thinking there should be a
way to get access to the directory in question in the first place.

I need the path so that I can write some data to a file there.

TIA,

--
Sean LeBlanc
Software Developer
insightamerica
"Those who do not understand Unix are condemned to reinvent it, poorly."
--Henry Spencer

-----Original Message-----
From: Keith Bohnenberger [mailto:kbohnenberger@mcdonaldbradley.com]
Sent: Wednesday, January 07, 2004 10:02 AM
To: axis-user@ws.apache.org
Subject: RE: Discovering the webapp path.


You can try getting the java system property user.dir
Why do you need the path?  Can you get away with using
getResourceAsStream(...) instead?


> -----Original Message-----
> From: Sean Leblanc [mailto:SeanL@insightamerica.com]
> Sent: Wednesday, January 07, 2004 11:40 AM
> To: 'axis-user@ws.apache.org'
> Subject: Discovering the webapp path.
>
> I'm hoping this isn't a FAQ somewhere. I did try googling and
searching
> the
> mailing list. Here goes:
>
> Is there a way to, at runtime, discover the path that the webapp is
in? I
> can't really rely on the root path being any particular path and doing
> absolute path, because depending on how tomcat is started, root is in
> different places.
>
>
> TIA,
>
> --
> Sean LeBlanc
> Software Developer
> insightamerica
> "Those who do not understand Unix are condemned to reinvent it,
poorly."
> --Henry Spencer
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