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From Matt Benson <gudnabr...@yahoo.com>
Subject Re: sort or min/max file
Date Thu, 21 Jul 2005 18:29:35 GMT
In Ant 1.7 you will be able to sort resource
collections (e.g. fileset) by various criteria
including timestamp.  At present nothing comes to mind
other than a custom task, scripting, or delegating to
an OS command such as dir or ls.

-Matt

--- "Schulpen, D.P.H." <D.P.H.Schulpen@student.tue.nl>
wrote:

> I'm trying to write a script to automate certain
> parts of unzipping the most recent build archive of
> an application (in this case NetBeans) in a certain
> location.
> 
> However, I can't figure out a way to determine the
> most recent file. I thought about uptodate.
> Unfortunately, I have no idea how to run the task
> for every file in a list against all other files in
> the list, and determine which one returns true. I
> could also use lexical sorting or min/max-ing on the
> filename, but can't seem to find a task that
> supports this.
> 
> Some mailing list archive browsing seemed to hint
> that what I'm trying to achive is not yet possible
> with 1.6.5. Is this correct? If not, any pointers?
> 
> 
>  - Daan
> 


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