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From Jacob Kjome <h...@visi.com>
Subject RE: Getting the name of the current file in a fileset
Date Wed, 04 Jun 2003 13:51:11 GMT

See:
http://nagoya.apache.org/bugzilla/show_bug.cgi?id=12368
http://nagoya.apache.org/bugzilla/show_bug.cgi?id=18715

Jake

At 02:26 PM 6/4/2003 +0100, you wrote:
>Would you explain where I can find out about this feature?
>
>Martin Roberts
>xml designer,
>BT Exact
>e-mail: martin.me.roberts@bt.com
>tel: +44(0) 1473 609785  clickdial
>fax: +44(0) 1473 609834
>Intranet Site :http://twiki.btlabs.bt.co.uk/twiki
>
>
>
>-----Original Message-----
>From: Antoine Levy-Lambert [mailto:levylambert@tiscali-dsl.de]
>Sent: 04 June 2003 13:52
>To: Ant Users List
>Subject: Re: Getting the name of the current file in a fileset
>
>
>What you are doing seems to be what the new <subant/> task of ant 1.6alpha
>is addressing. Antoine
>----- Original Message -----
>From: <martin.me.roberts@bt.com>
>To: <user@ant.apache.org>
>Sent: Wednesday, June 04, 2003 2:48 PM
>Subject: RE: Getting the name of the current file in a fileset
>
>
>Jan,
>How could I get multiple properties passed to the target being called from
>the foreach.  I need to set directories for the target to work with.
>
>Thanks
>
>Martin Roberts
>xml designer,
>BT Exact
>e-mail: martin.me.roberts@bt.com
>tel: +44(0) 1473 609785  clickdial
>fax: +44(0) 1473 609834
>Intranet Site :http://twiki.btlabs.bt.co.uk/twiki
>
>
>
>-----Original Message-----
>From: Jan.Materne@rzf.fin-nrw.de [mailto:Jan.Materne@rzf.fin-nrw.de]
>Sent: 04 June 2003 11:30
>To: user@ant.apache.org
>Subject: AW: Getting the name of the current file in a fileset
>
>
>I think the only way is to use AntContrib┬┤s <foreach>.
>This topic is already discussed on
>http://marc.theaimsgroup.com/?l=ant-user&m=104464267224692&w=2
>
>Maybe we can add a property ${xmlfile} which is set by <xslt> and can be
>used in nested <param> tags. <xslt dir="" xsl="">
>     <param name="thefile" value="${xmlfile}"/>
></xslt>
>So the stylesheet can use its "thefile".
>
>Maybe a little work in XSLTProcess.process(File baseDir, String xmlFile,
>File destDir, File stylesheet).
>
>
>Jan
>
>
>
>Ant-Contrib:
>   Homepage:   http://sourceforge.net/projects/ant-contrib/
>   CVS-Source:
>http://cvs.sourceforge.net/cgi-bin/viewcvs.cgi/ant-contrib/ant-contrib/src/n
>et/sf/antcontrib/
>   CVS-Manual:
>http://cvs.sourceforge.net/cgi-bin/viewcvs.cgi/ant-contrib/ant-contrib/manua
>l/index.html
>
>http://cvs.sourceforge.net/cgi-bin/viewcvs.cgi/*checkout*/ant-contrib/ant-co
>ntrib/manual/tasks/index.html
>   Binary:     http://gump.covalent.net/jars/latest/ant-contrib/
>
>
>
> > -----Urspr├╝ngliche Nachricht-----
> > Von: martin.me.roberts@bt.com [mailto:martin.me.roberts@bt.com]
> > Gesendet am: Mittwoch, 4. Juni 2003 12:10
> > An: user@ant.apache.org
> > Betreff: Getting the name of the current file in a fileset
> >
> > Hi,
> >         I need to get the current file name so I can pass it into the
> > xslt task as a value for the stylesheet.  How do I do this?  Is
> > there a property
> > for this?
> >
> > Martin Roberts
> >
> >
> >
>
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