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From: EXT / FOCAL MALAPRADE Roland <ext.focal.malaprade@sncf.fr>
To: "'Ant Users List'" <ant-user@jakarta.apache.org>
Subject: RE: Using ReplaceRegExp
Date: Thu, 26 Sep 2002 16:04:38 +0200
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okay that was actually the first thing I'd tried. later I used this:

<replaceregexp file="temptest.csv" match="^(([^;]*;){30})([^;]*)(;)$"
replace="\1\3" byline="true" />

This worked fine (it removed the 31rst semi-colon from each line). Then I
wanted to add 00 if the 31rst column of my CSV file was missing, so I think
I tried (sorry I deleted it) :

<replaceregexp file="temptest.csv" match="^(([^;]*;){30})$" replace="\100"
byline="true" />

now if I put replace="\1'00'", it added '00' to the end of each line where
the 32rst column was missing, but I didn't want the single quotes, but with
just \100 (as in \1 and 00), it didn't work. I supposed it interpreted it as
"give me the 100th result".

Now I read somewhere that you could match a caracter by using it's octal
value as \nnn, or its hexadecimal value with \x, but this is supposedly for
matching, and not for the replacement.

As i don't know much about regular expressions, it's got me beat. Any ideas?

Roland. 

-----Message d'origine-----
De : Stefan Bodewig [mailto:bodewig@apache.org]
Envoye : jeudi 26 septembre 2002 15:42
A : ant-user@jakarta.apache.org
Objet : Re: Using ReplaceRegExp


On Tue, 24 Sep 2002, <ext.focal.malaprade@sncf.fr> wrote:

> Thanks for that. now I wanted to add a value at the end
> 
> <replaceregexp file="temptest.csv" match="(.);$" 
>                replace="\1<a value>" byline="true" />
> 
> now if i put replace="\100" to add a '00' (reusing the result '\1'),
> it doesn't work.

What is the result?

\1 will only match the very last character of the line (in front of
the ";"), you probably want to use (.*) instead.

Stefan

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