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From Eugene Prokopiev <prokop...@stc.donpac.ru>
Subject Exception on sending message in XA environment
Date Tue, 19 Sep 2006 12:25:52 GMT
Hi,

I need to get exception on send message in XA environment to rollback 
transaction. In production I use Spring 2.0 with Message-Driven POJO, 
Jencks (as XA-enabled connection pool only) and JOTM. Production 
configuration is complex, so I write very simple sending message example 
in standalone XA environment:

public class Producer {

	public static void main(String[] args) throws Exception {
		
		// start transaction manager
		TMService jotm = new Jotm(true, false);
		UserTransaction transaction = jotm.getUserTransaction();
		TransactionManager transactionManager = jotm.getTransactionManager();
		
		// start connection
		ActiveMQXAConnectionFactory connectionFactory =
			new ActiveMQXAConnectionFactory("tcp://localhost:5000");
		XAConnection connection = connectionFactory.createXAConnection();
		XASession session = connection.createXASession();
		Destination destination = session.createQueue("error");
         MessageProducer producer = session.createProducer(destination);

         // send message
         TextMessage message = session.createTextMessage("Test Message 
String");
         transaction.begin();
 
transactionManager.getTransaction().enlistResource(session.getXAResource());
         System.out.println(transactionManager.getTransaction());
         try {
			producer.send(message);
		} catch (Exception e) {
			System.out.println("EXCEPTION!!! : "+e);
		}
         transaction.commit();
         System.out.println("sent message : "+message.getJMSMessageID());

         // close connection
         session.close();
         connection.close();
	}

}

I can run ActiveMQ with authorization, so user can connect but can't 
send message or nobody can't send message to destination 
"queue://error". In this case I got:

INFO  jotm - JOTM started with a local transaction factory which is not 
bound.
INFO  jotm - CAROL initialization
INFO  ConfigurationRepository - No protocols were defined for property 
'carol.protocols', trying with default protocol = 'jrmp'.
INFO  jta - JOTM 2.0.10
bb14:38:0:010f2192685af71b2c...f0a801:
WARN  ActiveMQConnection - Async exception with no exception listener: 
java.lang.Exception: Error destination
java.lang.Exception: Error destination
	at simple.RestrictPlugin.send(RestrictPlugin.java:14)
	at 
org.apache.activemq.broker.MutableBrokerFilter.send(MutableBrokerFilter.java:131)
	at 
org.apache.activemq.broker.AbstractConnection.processMessage(AbstractConnection.java:377)
	at 
org.apache.activemq.command.ActiveMQMessage.visit(ActiveMQMessage.java:603)
	at 
org.apache.activemq.broker.AbstractConnection.service(AbstractConnection.java:226)
	at 
org.apache.activemq.broker.TransportConnection$1.onCommand(TransportConnection.java:62)
	at 
org.apache.activemq.transport.ResponseCorrelator.onCommand(ResponseCorrelator.java:91)
	at 
org.apache.activemq.transport.TransportFilter.onCommand(TransportFilter.java:63)
	at 
org.apache.activemq.transport.WireFormatNegotiator.onCommand(WireFormatNegotiator.java:117)
	at 
org.apache.activemq.transport.InactivityMonitor.onCommand(InactivityMonitor.java:122)
	at 
org.apache.activemq.transport.TransportSupport.doConsume(TransportSupport.java:87)
	at 
org.apache.activemq.transport.tcp.TcpTransport.run(TcpTransport.java:127)
	at java.lang.Thread.run(Thread.java:595)
sent message : ID:prokopiev.stc.donpac.ru-51742-1158666713794-1:0:1:1:1


but I can't see EXCEPTION!!! row.

In more simple case without XA I see this exception:

public class Producer {

	public static void main(String[] args) throws Exception {
		
		ActiveMQConnection connection = 
ActiveMQConnection.makeConnection("tcp://localhost:5000");
	    connection.start();
	    Session session = connection.createSession(false, 
Session.AUTO_ACKNOWLEDGE);
	    Destination destination = session.createQueue("error");
	    MessageProducer producer = session.createProducer(destination);	 

	    TextMessage message = session.createTextMessage("Test Message String");
	    try {
			producer.send(message);
		} catch (Exception e) {
			System.out.println("EXCEPTION!!! : "+e);
		}
		session.close();
	    connection.close();
}

In this case I see:

EXCEPTION!!! : javax.jms.JMSException: Error destination

Is it possible to get exception on send message in XA environment?

--
Thanks,
Eugene Prokopiev


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