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Date: Mon, 16 Nov 2015 11:50:52 -0500
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Subject: Re: delete rows test result
From: William Slacum <wslacum@gmail.com>
To: dev <dev@accumulo.apache.org>
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"Reading" all of the rows first implies you're bringing back the entire
result to a client, which provides you serial access to the data.

I think you should re-run test #3 that measures the time it takes to call
deleteRows only. I'm emphasizing this because I've worked on projects that
could quickly define a range to be deleted without reading any data, and
using deleteRows decreased our latency significantly

On Mon, Nov 16, 2015 at 11:19 AM, z11373 <z11373@outlook.com> wrote:

> I didn't do that, but I am sure can extrapolate that from Test 1.
>
> Test 1 is doing:
> foreach k/v in scanner's iterator
>     create a new mutation with that row
>     call putDelete
>
> Test 3 is doing
> foreach k/v in scanner's iterator
>     assign the row of first entry to 'first' var
>     assign the row to a 'last' var
> After the loop is done, pass 'first' and 'last' vars to deleteRows.
>
> So, if I'd extrapolate the time without reading all rows, then we can
> subtract result from Test 1 from result from Test 3, i.e. for Table 1 is
> 196,597 - 5,702 = 190,895 (this is still way too long)
>
>
>
>
> --
> View this message in context:
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> Sent from the Developers mailing list archive at Nabble.com.
>

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